Integrate x^2 - 4x + 3 from 0 to 3: animated lesson
A narrated, step-by-step definite integrals video lesson with captions. Final answer: 0.
Video with a synthetic English voice and captions. Pick another language for subtitles in that language, or open the interactive version.
Video narrated by a synthetic voice (Piper TTS, en_US-ljspeech-high voice (LJ Speech dataset, public domain)); the steps come from our maths engine and the answer was checked independently. Download MP4 (0.5 MB) · Captions (WebVTT)
Steps on screen
- 1. The problemEvaluating an integral
- 2. Steps, part 1
- Start with the definite integral
- Power rule: ∫ xⁿ dx = xⁿ⁺¹/(n+1)
- Power rule: ∫ xⁿ dx = xⁿ⁺¹/(n+1)
- Constant multiple rule: ∫ k·f dx = k∫ f dx
- 3. Steps, part 2
- Sum rule: integrate term by term
- Constant rule: ∫ k dx = kx
- Sum rule: integrate term by term
- Antiderivative
- 4. Steps, part 3
- Apply the fundamental theorem of calculus
- 5. The answer
∫ from 0 to 3 = 0
- 6. Check
- Differentiated the antiderivative and compared it with the integrand ✓
- Adaptive Simpson's rule gives 0 ✓
Transcript
The problem. Here is the problem: integrate x squared minus 4x plus 3 from 0 to 3. Evaluate the definite integral of x squared minus 4 x plus 3 from x equals 0 to x equals 3.
Steps, part 1. Start with the definite integral. Power rule: the integral of x to the power n dx equals x to the power n plus 1/(n plus 1). Power rule: the integral of x to the power n dx equals x to the power n plus 1/(n plus 1). Constant multiple rule: the integral of k times f dx equals k the integral of f dx.
Steps, part 2. Sum rule: integrate term by term. Constant rule: the integral of k dx equals kx. Sum rule: integrate term by term. Antiderivative.
Steps, part 3. Apply the fundamental theorem of calculus.
The answer. So the answer is 0. A definite integral gives the signed area between the curve and the x-axis: area above the axis counts as positive and area below counts as negative.
Check. Differentiated the antiderivative and compared it with the integrand, which checks out. Adaptive Simpson prime s rule gives 0, which checks out.
About definite integrals
Evaluate definite integrals with the fundamental theorem of calculus.
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