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Systems of equationsAlgebraHigh schoolabout 1:11

Solve the system 3x - 8y = -50 and 5x + 2y = 24: animated lesson

A narrated, step-by-step systems of equations video lesson with captions. Final answer: x = 2, y = 7.

Video with a synthetic English voice and captions. Pick another language for subtitles in that language, or open the interactive version.

Video narrated by a synthetic voice (Piper TTS, en_US-ljspeech-high voice (LJ Speech dataset, public domain)); the steps come from our maths engine and the answer was checked independently. Download MP4 (0.5 MB) · Captions (WebVTT)

Steps on screen

  1. 1. The problem
    Solving an equation
    {3x−8y=−505x+2y=24\begin{cases} 3x-8y = -50 \\ 5x+2y = 24 \end{cases}
  2. 2. Steps, part 1
    1. {3x−8y=−505x+2y=24\begin{cases} 3x - 8y = -50 \\ 5x + 2y = 24 \end{cases}
      Write every equation in standard form
    2. [3−8−505224]\begin{bmatrix}3 & -8 & -50 \\ 5 & 2 & 24\end{bmatrix}
      Build the augmented matrix [A | b]
    3. Gauss–Jordan elimination
    4. R1→13R1: [1−83−5035224]R_{1} \to \tfrac{1}{3} R_{1}:\ \begin{bmatrix}1 & -\frac{8}{3} & -\frac{50}{3} \\ 5 & 2 & 24\end{bmatrix}
      Divide R1 by 3
  3. 3. Steps, part 2
    1. R2→R2−5R1: [1−83−50304633223]R_{2} \to R_{2} - 5R_{1}:\ \begin{bmatrix}1 & -\frac{8}{3} & -\frac{50}{3} \\ 0 & \frac{46}{3} & \frac{322}{3}\end{bmatrix}
      Clear column 1 using the pivot in R1
    2. R2→1463R2: [1−83−503017]R_{2} \to \tfrac{1}{\frac{46}{3}} R_{2}:\ \begin{bmatrix}1 & -\frac{8}{3} & -\frac{50}{3} \\ 0 & 1 & 7\end{bmatrix}
      Divide R2 by 46/3
    3. R1→R1+83R2: [102017]R_{1} \to R_{1} + \frac{8}{3} R_{2}:\ \begin{bmatrix}1 & 0 & 2 \\ 0 & 1 & 7\end{bmatrix}
      Clear column 2 using the pivot in R2
    4. [102017]\begin{bmatrix}1 & 0 & 2 \\ 0 & 1 & 7\end{bmatrix}
      Reduced row-echelon form
  4. 4. Steps, part 3
    1. x=2, y=7x = 2,\ y = 7
      Read off the unique solution
  5. 5. The answer
    x=2, y=7x = 2,\ y = 7

    3x - 8y = -50; 5x + 2y = 24 ⇒ x = 2, y = 7

  6. 6. Check
    • Equation 1: 3x - 8y = -50 ✓
    • Equation 2: 5x + 2y = 24 ✓

Transcript

The problem. Here is the problem: 3x minus 8y equals negative 50; 5x plus 2y equals 24. 2 linear equations in 2 unknowns (x, y).

Steps, part 1. Write every equation in standard form. Move all variable terms to the left and constants to the right. Build the augmented matrix [A | b]. Columns: x, y | constant. Gauss–Jordan elimination. Use row operations to make each pivot 1 and clear the rest of its column. Divide R1 by 3.

Steps, part 2. Clear column 1 using the pivot in R1. Divide R2 by 46 over 3. Clear column 2 using the pivot in R2. Reduced row-echelon form.

Steps, part 3. Read off the unique solution.

The answer. So the answer is x equals 2, y equals 7. The system has exactly one solution; substituting it back satisfies every equation.

Check. Equation 1: 3x minus 8y equals negative 50, which checks out. Equation 2: 5x plus 2y equals 24, which checks out.

About systems of equations

Solve systems of two or three linear equations by elimination and substitution.

Solve the system 3x - 8y = -50 and 5x + 2y = 24 (Lesson)