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Systems of equationsAlgebraHigh schoolabout 1:12

Solve the system -9x - 2y = -25, 9x + y = 26: animated lesson

A narrated, step-by-step systems of equations video lesson with captions. Final answer: x = 3, y = -1.

Video with a synthetic English voice and captions. Pick another language for subtitles in that language, or open the interactive version.

Video narrated by a synthetic voice (Piper TTS, en_US-ljspeech-high voice (LJ Speech dataset, public domain)); the steps come from our maths engine and the answer was checked independently. Download MP4 (0.5 MB) · Captions (WebVTT)

Steps on screen

  1. 1. The problem
    Solving an equation
    {−9x−2y=−259x+y=26\begin{cases} -9x-2y = -25 \\ 9x+ y = 26 \end{cases}
  2. 2. Steps, part 1
    1. {−9x−2y=−259x+y=26\begin{cases} -9x - 2y = -25 \\ 9x + y = 26 \end{cases}
      Write every equation in standard form
    2. [−9−2−259126]\begin{bmatrix}-9 & -2 & -25 \\ 9 & 1 & 26\end{bmatrix}
      Build the augmented matrix [A | b]
    3. Gauss–Jordan elimination
    4. R1→1−9R1: [1292599126]R_{1} \to \tfrac{1}{-9} R_{1}:\ \begin{bmatrix}1 & \frac{2}{9} & \frac{25}{9} \\ 9 & 1 & 26\end{bmatrix}
      Divide R1 by -9
  3. 3. Steps, part 2
    1. R2→R2−9R1: [1292590−11]R_{2} \to R_{2} - 9R_{1}:\ \begin{bmatrix}1 & \frac{2}{9} & \frac{25}{9} \\ 0 & -1 & 1\end{bmatrix}
      Clear column 1 using the pivot in R1
    2. R2→1−1R2: [12925901−1]R_{2} \to \tfrac{1}{-1} R_{2}:\ \begin{bmatrix}1 & \frac{2}{9} & \frac{25}{9} \\ 0 & 1 & -1\end{bmatrix}
      Divide R2 by -1
    3. R1→R1−29R2: [10301−1]R_{1} \to R_{1} - \frac{2}{9} R_{2}:\ \begin{bmatrix}1 & 0 & 3 \\ 0 & 1 & -1\end{bmatrix}
      Clear column 2 using the pivot in R2
    4. [10301−1]\begin{bmatrix}1 & 0 & 3 \\ 0 & 1 & -1\end{bmatrix}
      Reduced row-echelon form
  4. 4. Steps, part 3
    1. x=3, y=−1x = 3,\ y = -1
      Read off the unique solution
  5. 5. The answer
    x=3, y=−1x = 3,\ y = -1

    -9x - 2y = -25; 9x + y = 26 ⇒ x = 3, y = -1

  6. 6. Check
    • Equation 1: -9x - 2y = -25 ✓
    • Equation 2: 9x + y = 26 ✓

Transcript

The problem. Here is the problem: negative 9x minus 2y equals negative 25; 9x plus y equals 26. 2 linear equations in 2 unknowns (x, y).

Steps, part 1. Write every equation in standard form. Move all variable terms to the left and constants to the right. Build the augmented matrix [A | b]. Columns: x, y | constant. Gauss–Jordan elimination. Use row operations to make each pivot 1 and clear the rest of its column. Divide R1 by negative 9.

Steps, part 2. Clear column 1 using the pivot in R1. Divide R2 by negative 1. Clear column 2 using the pivot in R2. Reduced row-echelon form.

Steps, part 3. Read off the unique solution.

The answer. So the answer is x equals 3, y equals negative 1. The system has exactly one solution; substituting it back satisfies every equation.

Check. Equation 1: negative 9x minus 2y equals negative 25, which checks out. Equation 2: 9x plus y equals 26, which checks out.

About systems of equations

Solve systems of two or three linear equations by elimination and substitution.

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Solve the system -9x - 2y = -25, 9x + y = 26 (Lesson)