The Definite Integral as Area
Find the area under y = x² + 1 from 0 to 2 with an antiderivative and the Fundamental Theorem of Calculus: 14/3, about 4.67 square units.
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On-screen maths
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- 1. The question0:00
area under on - 2. Antiderivative0:14
- 3. Fundamental Theorem0:24
- 4. Recap0:40
- Find any antiderivative .
- .
- Above the axis, the integral is the area.
About integrals
Antiderivatives, substitution and the Fundamental Theorem.
Practise what you just watched
The Fundamental Theorem with the power rule for antiderivatives.
Antiderivative x squared, evaluated at the bounds.
A basic trigonometric antiderivative; do not forget the constant.
The area of a triangle with base 4 and height 4.
- Integral Calculator: try the same kind of problem with your own numbers.
- Definite Integral Calculator: try the same kind of problem with your own numbers.
- More calculus practice problems
- Limits Study Guide (study guide)
- AP Calculus AB Unit 6: Integration and Accumulation of Change: the AP unit this lesson supports.
- Calculus calculators and topics
- Step-by-step solver: check your own answer with hints.
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