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Definite integralsCalculusCollegeabout 0:55

Definite integral of sqrt(x) from 1 to 9: animated lesson

A narrated, step-by-step definite integrals video lesson with captions. Final answer: 52/3 ≈ 17.333333.

Video with a synthetic English voice and captions. Pick another language for subtitles in that language, or open the interactive version.

Video narrated by a synthetic voice (Piper TTS, en_US-ljspeech-high voice (LJ Speech dataset, public domain)); the steps come from our maths engine and the answer was checked independently. Download MP4 (0.4 MB) · Captions (WebVTT)

Steps on screen

  1. 1. The problem
    Evaluating an integral
    ∫19x dx\int_{1}^{9} \sqrt{x}\,dx
  2. 2. Step by step
    1. ∫19x dx\int_{1}^{9} \sqrt{x}\,dx
      Start with the definite integral
    2. ∫x dx=x32⋅23\int \sqrt{x}\,dx = \frac{{x}^{\frac{3}{2}}\cdot2}{3}
      ∫ √x dx = (2/3)x^(3/2)
    3. F(x)=x32⋅23F(x) = \frac{{x}^{\frac{3}{2}}\cdot2}{3}
      Antiderivative
    4. F(9)−F(1)=18−0.6666666667=523≈17.333333F(9) - F(1) = 18 - 0.6666666667 = \frac{52}{3} \approx 17.333333
      Apply the fundamental theorem of calculus
  3. 3. The answer
    ∫19x dx=523≈17.333333\int_{1}^{9} \sqrt{x}\,dx = \frac{52}{3} \approx 17.333333

    ∫ from 1 to 9 = 52/3 ≈ 17.333333

  4. 4. Check
    • Differentiated the antiderivative and compared it with the integrand ✓
    • Adaptive Simpson's rule gives 17.33333333 ✓

Transcript

The problem. Here is the problem: integral of sqrt(x) from 1 to 9. Evaluate the definite integral of sqrt(x) from x equals 1 to x equals 9.

Step by step. Start with the definite integral. the integral of the square root of x dx equals (2 over 3)x to the power 3 over 2). Antiderivative. Apply the fundamental theorem of calculus.

The answer. So the answer is 52 over 3 approximately 17.333333. A definite integral gives the signed area between the curve and the x-axis: area above the axis counts as positive and area below counts as negative.

Check. Differentiated the antiderivative and compared it with the integrand, which checks out. Adaptive Simpson prime s rule gives 17.33333333, which checks out.

About definite integrals

Evaluate definite integrals with the fundamental theorem of calculus.

Definite integral of sqrt(x) from 1 to 9: Animated Lesson